Question

1. Construct a triangle ABC in which BC= 7cm, 4B = 75° and AB +AC = 13 cm.
2. Construct a triangle ABC in which BC = 8cm, B = 45° and AB -AC = 3.5 cm.
Construct a triangle PQR in which QR = 6cm, ZQ = 60° and PR-PQ=2cm.
Construct a triangle XYZ in which ZY=30°, Z = 90° and XY+YZ+ZX = 11 cm
5. Construct a right triangle whose base is 12cm and sum of its hypotenuse and other
3.
side is 18 cm.

plzz help me ..​

Answer 1

Answer:

1.Steps of Construction

(i) Draw BC = 7 cm.

(ii) Construct ∠YBC = 75°.

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD meeting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Justification

Since A lies on the perpendicular bisector of CD.

∴ AC = AD

Now BD = 13 cm

⇒ BA + AD = 13 cm

⇒ BA + BC = 13cm

Hence, △ABC is the required triangle.