Question

1. Construct
triangle ABC in which BC27cm, LB=25 and
ABTAC = 13cm.​

Answer 1

Answer:

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Step-by-step explanation:

1. Draw base BC of length 7 cm

2. Now, let's draw angle B = 75°

Let the ray be BX

3. Open the compass to length AB + AC = 13 cm.

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4. Join CD

5. Now, we will draw perpendicular bisector of CD

6. Mark point A where perpendicular bisector intersects BD

7. Join AC