(1-cos square theta )sec square theta =tan square theta
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(1-cos²theta)sec²theta
sin²theta×1/cos²theta
sin²theta/cos²theta
tan²theta
Answered by
1
Answer:
1-cos^2 theta = sin^2 theta,
sec^2 theta = 1/cos^2 theta
sin^2 theta / cos^2 theta = tan^2 theta,
LHS= RHS..
hence proved..
hope it is helpful..
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