Question

1-cos theta/1+cos theta +1+cos theta/1-cos theta =2/2sin theta-1

Answer 1

(1 - cos)/( 1 + cos) + (1 + cos)/( 1 - cos) = 2/(2sin -1)
taking LCM of lhs we get:-
{(1 - cos)^2 + (1 + cos)^2} / (1 - cos^2) = 2/(2sin -1)
on solving you'll get:-
(2 + 2cos^2)/ sin^2 = 2/(2sin -1)
( 1 + cos^2)/ sin^2 = 1/(2sin -1)
cross multiply, and solve then you'll get:-
2 = 2sin( 1 - cos^2)
1 = sin × sin^2
sin = 1
theta = 90.
thanks....