Question

check the correctness of given equation E=mc2 by the method of dimension​

Answer 1

• here E - energy which will have dimensional formula = M L^2 T^-2

• m - mass = M

• C - velocity of light = LT^-1

so,

E = mC^2.

=> [M L^2 T-2] = [M]×[L T^-1]^2

=> [M L^2 T-2] = [M] ×[L^2 T^-2

therefore [M L^2 T-2] = [M L^2 T^-2]