Question

If AB equal to 8 and a + b equal to 6 then the value of (a square + b square)

Answer 1

Answer:

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$ab = 8 \\ \\ a + b = 6 \\ \\ {a}^{2} + {b}^{2} =? \:$

➡ by using

$(a + b {)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ (6 {)}^{2} = {a}^{2} + {b}^{2} + 2 \times 8 \\ \\ 36 - 16 = {a}^{2} + {b}^{2} \\ \\ 20 = {a}^{2} + {b}^{2}$

Hope it helps ✨❤

Answer 2

Answer:

$\huge{\mathfrak{\underline{\orange{Answer}}}}$

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Step by step explanation

_______________ ____________

Given:-

ab= 8

a+b=6

To find :-

a^2+ b^2= ?

Solution:-

(a+b)^2 =a^2+b^2+2ab

substitute the known values:-

(6)^2=a^2+b^2+2(8)

36-16=a^2+ b^2

a^2+b^2=20

Verification:-

________________

Substitute all values

(a+b)^2=a^2+b^2+2ab

(6)^2=20+2(8)

36=36

LHS=RHS

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Hence we get answer;)

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