Question

1+cos theta/1 -cos theta= tan^2 theta/2
prove that ​

Answer 1

Step-by-step explanation:

L.H.S. = (1+cot 2 θ)(1−cosθ)(1+cosθ)

⇒ L.H.S. = (1+cot 2 θ)(1−cos 2 θ)

⇒ L.H.S. = cosec 2θsin 2 θ

[∵1+cot 2 θ=cosec 2 θand1−cos 2θ=sin 2 ]

⇒ L.H.S. = cosec 2 θsin 2 θ

⇒ L.H.S. = sin 2 θ1 ×sin 2 θ=1=R.H.S. [∵cosecθ sinθ1

∴cosec 2θ sin1]

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