Question

1+cos theta+sin theta/1+costheta-sintheta=1+sintheta/costheta in

Answer 1

what is this ...............

Answer 2

Answer:

Step-by-step explanation:

Given,

L.H.S. = 1 + cos θ + sinθ/1 + cosθ - sinθ

Multiplying the numerator and denominator by (1 + sin θ)

= {(1 + cos θ + sin θ} {(1 + + sin θ)}/{(1 + cos θ - sin θ)} {1 + sin θ}

= {1 + cos θ + sin θ} {(1 + + sin θ)}/{1 + cos θ) - sinθ + sinθ + sinθcosθ - sin^2 θ}

= (1 + cosθ + sinθ) (1 + sin θ)/(cos^2 θ + cosθ + sinθ cos θ)

= (1 + cosθ + sinθ) (1 + sinθ)/ cos θ (cosθ + 1 + sinθ)

= 1 + sinθ/cosθ

= R.H.S.