1-cos theta/sin theta=tan theta/2
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How to prove 1+sinθ−cosθ1+cosθ+sinθ=tan(θ2)?
Trigonometry
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P dilip_k
Jul 10, 2017
LHS=1+sinθ−cosθ1+cosθ+sinθ
=sinθ(1+sinθ−cosθ)sinθ(1+cosθ+sinθ)
=sinθ+sin2θ−sinθcosθsinθ(1+cosθ+sinθ)
=sinθ−sinθcosθ+(1−cos2θ)sinθ(1+cosθ+sinθ)
=sinθ(1−cosθ)+(1−cos2θ)sinθ(1+cosθ+sinθ)
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