Question

1-cos theta upon sin theta= sin theta upon 1 plus cos theta

Answer 1

Answer:

$\frac{1-cosA}{sinA} = \frac{sinA}{1+cosA}$

L.H.S.

$\frac{1-cosA}{sinA}$

multiplying the numerator and the denominator with (1+cosA)

$\frac{1-cosA}{sinA} * \frac{1+cosA}{1+cosA}$

$\frac{(1+cosA)(1-sinA)}{sinA + sinA.cosA}$

$\frac{(1+cosA)(1-cosA)}{sinA(1+cosA)}$

$\frac{1-cosA}{sinA}$

Hence proved!

Explanation: