Question

(1-cos²A) - sec² B + tan² B (1-sin²A) = sin²A + tan² B​

Answer 1

Step-by-step explanation:

= sin²A - sec²A + tan²Acos²A

= sin²A - 1/cos²A + sin² A

= (sin²Acos²A - 1 +sin²Acos²A)/cos²A

= (2sin²Acos²A-1)/cos²A

=

QUESTION MUST BE WRONG PLZ RECHECK

Answer 2

Step-by-step explanation:

(1 - cos²A) sec²B + tan²B (1-sin²A) = sin²A + tan²B

• 1 - cos²A = sin²A

sin²A sec²B + tan²B - tan²A sin²A = sin²A + tan²B

sin²A ( sec²B - tan²A ) + tan²B = sin²A + tan²B

• sec²B - tan²A = 1

sin²A + tan²B = sin²A + tan²B