Question

√1+cosA/1-cosA=1+cosA/sinA

Answer 1

Step-by-step explanation:

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Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value: \\\\\sqrt{\frac{1+cosA}{1-cosA}} \ = \frac{1+cosA}{sin A}\\\\\ Solution:\\\\\ L.H.S \\\\ \rightarrow \sqrt{\frac{1+cosA}{1-cosA}}\times\sqrt{\frac{1+cosA}{1+cosA}} \\\\ \rightarrow \sqrt{\frac{1+cosA}{1-cosA}\times\frac{1+cosA}{1+cosA}} \\\\ \rightarrow \sqrt{\frac{(1+cosA)(1+cosA)}{1^2-cos^2A}}\\\\ \rightarrow \sqrt{\frac{(1+cosA)^2}{1-cos^2A}}\\\\ \rightarrow \sqrt{\frac{(1+cosA)^2}{sin^2A}}\\\\ \rightarrow \frac{(1+cosA)}{sinA}$

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