(1+cosA) (1-cosA) =3/4 find sec A
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(1+cosA)(1-cosA)=3/4
(1)^2_(cosA)^2=3/4
1_cos^2A=3/4
1_3/4=cos^2A
4-3/4=cos^2A
1^4=cos^2A
1/2=cos^A
we know secA=1/cosA
so secA=2 is answer
(1)^2_(cosA)^2=3/4
1_cos^2A=3/4
1_3/4=cos^2A
4-3/4=cos^2A
1^4=cos^2A
1/2=cos^A
we know secA=1/cosA
so secA=2 is answer
shashank87:
we have to a squrare minus b square formula ....... inst it
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