Question

(1-cosA)(1+secA) = tanA sinA

Answer 1

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Answer 2

when we multiply then the equation will be. 1 + SecA - CosA - CosA SecA. we can write SecA as 1/CosA then eq. will be 1 + 1/CosA - CosA -1 then. 1-Cos*2A/CosA we can write 1-cos*2A as Sin*2A then. Sin*2A/CosA as TanA SinA