Math, asked by peeter804, 9 months ago

1÷cosa+sina-1+1÷cosa+sina+1=coseca+seca

Answers

Answered by sandy1816

1

Step-by-step explanation:

1/cosA+sinA-1+1/cosA+sinA+1

=cosA+sinA+1+cosA+sinA-1/(cosA+sinA)²-1

=2(cosA+sinA)/cos²A+sin²A+2cosAsinA-1

=2(cosA+sinA)/2cosAsinA

=(cosA+sinA)/cosAsinA

=cosA/cosAsinA+sinA/cosAsinA

=1/sinA+1/cosA

=cosecA+secA

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