1+cosA-sinA^2A/sinA[1+cosA]=cotA some1 help me out of it
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4
Answer: LHS,
cosA+1-sin²A/sinA[1+cosA]
cosA+cos²A/sinA[1+cosA] ----[1-sin²A=cos²A]
cosA[cosA+1]/sinA[cosA+1]
cosA/sinA
=cotA
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
Atleast last bye tu bolo
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