Question

1+cosA/sinA + sinA/1+cosA =2/sinA....

Justify your answer.

Answer 1

I hope it's help u................

Answer 2

Hello friend

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Here is your answer!!!

$\frac{1 + \cos \: a }{ \sin \: a } + \frac{ \sin \: a }{1 + \cos \: a } \\ \\=> \frac{(1 + \cos \: a) {}^{2} }{ (\sin \: a)} + \frac{ \sin {}^{2} a}{(1 + cos \: a)} \\ \\=> \frac{1 + 2cos \: a \: + cos {}^{2} \: a + sin {}^{2} a}{(sin \: a)(1 + cos \: a)} \\ \\=> \frac{2 + 2cos \: a}{(sin \: a)(1 + cos \: a} \\ \\ =>\frac{2(1 + cos \: a)}{sin \: a \: (1 + cos \: a)} \\ \\ =>\frac{2}{sin \: a}$
: L.H.S = R.H.S

We have proved.....

Thanks.

:)