Question

(1+COSA/
sinA)+
(sinA/
1+cotA)=2coseca​

Answer 1

Answer:

your question is wrong

it should be  1+cosA/sinA + sinA/1+cosA = 2cosecA

Step-by-step explanation:

((1+cosA)² + sin²A)/sinA(1+cosA)   (cross multipling for lcm)

(1² + cos²A + 2cosA + sin²A)/ sinA(1 + cosA)

since cos²A + sin²A=1 ,

(2+2cosA)/sinA(1+cosA)

2(1+cosA)/sinA(1+CosA)          (cancelling 1+cosA)

2/sinA

=2cosec A

hope it helps

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