Math, asked by pothy, 1 year ago

(1+cosec)(1-sin)=cos-cot

Answers

Answered by Anonymous1756

(cotA -cosA)/(cotA + cosA)
((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA
taking cosA common from numretor nd denominatr nd cancelling it we get
((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA
therfore
(cosecA-1)/(cosecA+1)

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