1+cosec a /cosec a =sin^2a /1 - sin a
Prove that LHS=RHS
Fastttt
Answers
Answered by
0
(1+cosec a)/cosec a
as we know that cosec a = 1/sin a
then
= (1 + 1/ sin a)/(1/sin a)
= [(sin a + 1)/sin a] * sina
= (1+sin a)*(1-sin a)/(1-sin a)
= (1-sin²a)/(1-sin a)
= cos²a /(1-sin a)
NeelamG:
plz check your statement
Similar questions