Question

(3p² qr^-2/2p^-1 q³) = (2p³r)^-1​

Answer 1

Answer:

ANSWER

(2p - 3q) + (3r - 2q) - (4p - 2r)

= (2.1 - 3.2) + (3.(-2) - 2.2) - (4.1 - 2.(-2))

[by substituting the value of p, q, r]

= (2 - 6) + (-6 - 4) - (4 + 4)

= (-4) + (-10) - (8)

= -4 - 10 - 8

= -(4 + 10 + 8)

= -22

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