1/cosec theta - cot theeta - 1/ sintheta =1/sin theeta - 1/cosec theeta + cot theeta
Answers
Answered by
2
hope it is helpful for you
Attachments:
vasundhara4:
please write neat
Answered by
0
( sin²A - cotA - 1 / sinA) = LHS
( cos²A - cotA - 1/ sinA)
=>( cos²A / sinA ) + ( cotA )
=>( 1-sin²A / sinA ) +( cotA )
=> ( 1 / sinA ) - ( 1 / cosecA ) + ( cotA ) = RHS
hope this answer helped u
( cos²A - cotA - 1/ sinA)
=>( cos²A / sinA ) + ( cotA )
=>( 1-sin²A / sinA ) +( cotA )
=> ( 1 / sinA ) - ( 1 / cosecA ) + ( cotA ) = RHS
hope this answer helped u
Similar questions