Math, asked by vnitinhariharan, 1 year ago

1/(cosecA+cosA) - 1/sinA = 1/sinA - 1/(cosecA-cosA)

Answers

Answered by proraider

2

LHS=1/(cosecA-cotA) -1/sinA

=(cosecA+cotA)/cosec^2A-cot^2A) -cosecA

=cosecA+cotA-cosecA

=cotA

RHS=1/sinA-1/(cosecA+cotA)

=cosecA-(cosecA-cotA)/(cosec^2A-cot^2A)

=cosecA-(cosecA-cotA)

=cotA

LHS=RHS

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