Math, asked by yashbarik, 1 year ago

(1+cot^2A)tanA/sec^2=cotA

Answers

Answered by laksssss
6
1+cot²A=cosec²A

∴(cosec²A×tanA)/sec²A

=(1/sin²A×sinA/cosA)(cos²A)

=cosA/sinA

=cotA
Answered by anitha18121
5
hope it helps to you..........
.. please mark it as brainlist answer please
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