Question

1+cot^2O/1+cosecO=cosecO

Answer 1

Answer:

COSec 0–1 COSec 6 + 1 coseco 6 [cosec{}+1 -cosec{}+1] coseco 0–1 2Cosec 6 cott 6 2 sin” 0 sin” 0 cost 6 = 2 seco) = RHS 1 Q. 6.

Step-by-step explanation:

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