Question

(1 + cot 60°)^2/
(1-сot 60°)
=
(1+ cos 30°)/
(1 - cos 30°)
​

Answer 1

[(1+cot60°)/(1-cot60°)]²=

[(sin60°+cos60°)/(sin60°-cos60°)]²

[sin²60+cos²60+2sin60.cos60]/[sin²60+cos²60-2sin60.cos60]=

{1+sin120°}/{1-sin120°}=

{1+sin(90+30)}/{1-sin(90+30)}

={1+cos30°}/{1-cos30°}.

for..=> sin(90+©)=cos©

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