Question

(1 + cot square theta) (1 - cos theta 1) + cos theta = 1​

Answer 1

$identities \\ \\ \\ { \sin}^{2} x + { \cos }^{2} x = 1 \\ \\ \\ 1 + { \cot}^{2} x = { \csc }^{2} x\\ \\ \\ now \: on \: lhs \\ \\ \\ (1 + { \cot }^{2}x)(1 - { \cos }^{2} x) \\ \\ \\ = { ( \csc }^{2} x)( { \sin}^{2} x) \\ \\ \\ = \frac{1}{ { \sin }^{2}x } { \sin}^{2} x \\ \\ \\ = 1 \\ \\ \\ = rhs$

THANKS.