Question

(1+cot theta).sin square theta = 1​

Answer 1

Step-by-step explanation:

$(1 + \cot( \alpha ) { \sin }^{2} \alpha = 1 \\ \\ = ( 1 + \frac{ \cos( \alpha ) }{ \sin( \alpha ) } ) { \sin }^{2} \alpha \\ \\ = \frac{ \sin( \alpha ) + \cos( \alpha ) }{ \sin( \alpha ) } { \sin }^{2} \alpha \\ \\ = ( \: \sin( \alpha ) + \cos( \alpha ) ) \sin( \alpha )$