Question

(1+cot tita-cosec tita) (1+tan tita+sec tita)=2​

Answer 1

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Answer 2

Answer:

(1+cotA-cosecA)(1+tanA+secA)=2

lhs=(1+cosA/sinA-1/sinA)(1+sinA/cosA+1/cosA)

=(sinA +cosA-1/sinA)(cosA+sinA+1/cosA)

=(sinA +cosA )^2-1/cosAsinA

=sin^2A+cos^2A+2sinAcosA/sinAcosA

=1 -1+2sinAcosA/sinAcosA

=2.