(1+cot²theta)(1+cos theta)(1-cos theta)=1
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(1+cot²θ)(1-cosθ)(1+cosθ)=1--------Equation 1
(1+cosθ)(1-cosθ) is of the form (a+b)(a-b)=a²-b²
(1+cosθ)(1-cosθ)=1-cos²θ
But 1-cos²θ=sin²θ
So equation 1 changes to
=(1 + cot²θ )(sin²θ)
=sin²θ+cot²θsin²θ
=sin²θ+(cos²θ*sin²θ/sin²θ)
=sin²θ+cos²θ
=1
Step-by-step explanation:
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