Math, asked by vbtarapur, 2 months ago

(1 + cotA - cosecA) (1 + tanA + secA)?

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Answered by sandy1816

$(1 + cota - coseca)(1 + tana + seca) \\ \\ = ( \frac{sina + cosa - 1}{sina} )( \frac{cosa + sina - 1}{cosa} ) \\ \\ = \frac{( {sina + cosa})^{2} - 1 }{sinacosa} \\ \\ = \frac{2sinacosa}{sinacosa} \\ \\ = 2$

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(1 + cotA - cosecA) (1 + tanA + secA)?​

Answers

(1 + cotA - cosecA) (1 + tanA + secA)?