(1+cotA+tanA)(SinA-cosA)=secA/cosec*2A-cosecA/sec*2A
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ahead...
taking lcm
=sin^3A - cos^3A/ sinA*cosA - (ii)
From i and ii
LHS=RHS
taking lcm
=sin^3A - cos^3A/ sinA*cosA - (ii)
From i and ii
LHS=RHS
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123piya58:
thanku so much
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Answered by
4
Step-by-step explanation:
(1+ cotA+ tanA).(sinA-cosA)= secA\cosec square A- cosecA/sec square A
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