Question

The number of oxygen atoms in 4.4 g of C{{O}_{2}}
is approx. [CBSE PMT 1990]
A) 1.2\times {{10}^{23}} B) 6\times {{10}^{22}} C) 6\times {{10}^{23}} D) 12\times {{10}^{23}}

Answer 1

heyy dear sumiya ur answer...........

Molar mass CO2 = 44 g/mol You have 4.4g , so you have 4.4/44 = 0.1 mol CO2 1mol CO2 has 6.022*10^23 molecules 0.1mol CO2 has (6.022*10^23)*0.1 = 6.022*10^22 molecules 1molecule of CO2 contains 2 atoms of O Therefore, 6.022*10^22 molecules of CO2 will contain (6.022*10^22) *2 = 1.204*10^23 atoms O
hope it will help u...............@kundan