Math, asked by Gzaghgcbbgvbnnbvvvvb, 1 year ago

(1+cotA+tanA)(sinA-cosA)=sinAtanA-cotAcosA

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Answered by 9917699562

L.H.S = (1+cotA+tanA)(sinA-cosA)
= (sinA+sinAcotA +tanAsinA-cosA -cosAcotA -tanAcosA)
=(sinA+sinAcosA/sinA+tanAsinA-cosA-cosAcotA -cosAsinA/cosA)
= (sinA+cosA+tanAsinA -cosA- cosAcotA -sinA)
= tanAsinA -cosAcotA
= sinAtanA-cotAcosA

Answered by amruthaabi

Hope this helps. Please mark as brainliest

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