Math, asked by ankitsinghkv7092, 8 months ago

(1+cotA+tanA)(Sins-Cost)=SinA×tanA=cotA×cosA

Answers

Answered by sandy1816

0

Step-by-step explanation:

(1+cotA+tanA)(sinA-cosA)

=(sinAcosA+1/sinAcosA)(sinAcosA)

=(sin³A-cos³A)/sinAcosA

=sin²A/cosA-cos²A/sinA

=sinAtanA-cosAcotA

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