Math, asked by ankitsinghkv7092, 9 months ago

(1+cotA+tanA)(Sins-Cost)=SinA×tanA=cotA×cosA

Answers

Answered by sandy1816
0

Step-by-step explanation:

(1+cotA+tanA)(sinA-cosA)

=(sinAcosA+1/sinAcosA)(sinAcosA)

=(sin³A-cos³A)/sinAcosA

=sin²A/cosA-cos²A/sinA

=sinAtanA-cosAcotA

Similar questions