1)Determine the area of a square whose perimeter is 80 cm.
2)Calculate which one has the larger area and by how much: a square of
side 16 cm or a rectangle of dimensions 20 cm by 13 cm.
Answers
Answer:
1.) Area of square = 400 sq. cm
2.) Area of rectangle is more than the area of square by 4 sq. cm
Thus rectangle has the larger area.
Step-by-step explanation:
1.) Let the side of a square be 'a'.
Given,
Perimeter of square = 80 cm ... (1)
We know that,
Perimeter of a square = 4a ... (2)
From eq. (1) and eq. (2) , we get
=> 4a = 80
=> a = 20 cm
Hence side of square = 20 cm
We know that,
Area of square = (side)^2
Then, by applying value we get,
Area of square = a^2
=> area of square = (20) ^2
=> area of square = 20×20
=> Area of square = 400 sq. cm
Hence, the area of square =
= 400 sq. cm
2.) Given,
side of square = 16 cm
dimensions of rectangle =
= 20cm × 13cm
Area of square = (side)^2
=> Area of square = (16)^2
=> Area of square = 16 × 16
=> Area of square = 256 sq. cm
Hence, area of square = 256 sq. cm
Now,
Area of rectangle = l×b
=> Area of rectangle = 20cm×13cm
=> Area od rectangle = 260 sq. cm
Hence,
Area of rectangle = 260 sq. cm
Clearly we can see that, area of rectangle is more than the area of square.
Area of rectangle > Area od square
=> 260 sq. cm > 256 sq. cm
By,
Difference = Area of rectangle - Area of square
= 260 - 256
= 4 sq. cm
Hence, area of rectangle is more than the area of square by 4 sq. cm
Thus rectangle has the larger area.
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