Question

(1) Determine the point on the graph of the linear equation 2x — 7y = 49, whose ordinate is equal to abscissa.
(2) When a number is divided by another number the quotient and reminder obtained are 9 and 1 respectively. Express this as linear equation in two variable

Answer 1

Answer:

1. since ordinate is equal to abscissa

1. since ordinate is equal to abscissay=x

1. since ordinate is equal to abscissay=xlet's take it as one variable p

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.Thus, x is the dividend and y is divisor.

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.Thus, x is the dividend and y is divisor.Given quotient=9 and remainder =1

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.Thus, x is the dividend and y is divisor.Given quotient=9 and remainder =1We know that Dividend=Divisor * Quotient +Remainder

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.Thus, x is the dividend and y is divisor.Given quotient=9 and remainder =1We know that Dividend=Divisor * Quotient +RemainderThus we get x=9y+1 i.e. x-9y=1

1. since ordinate is equal to abscissay=xlet's take it as one variable pso, 2p-7p=49 -5p=49 p=-49/5therfore the point is (-49/5 , -49/5)2. Let first number be x and the number with which it is divided be y.Thus, x is the dividend and y is divisor.Given quotient=9 and remainder =1We know that Dividend=Divisor * Quotient +RemainderThus we get x=9y+1 i.e. x-9y=1Required linear equation is x-9y=1.

Step-by-step explanation:

I Just hope it was right answer!!