Question

1. Determine the resultant of the four forces acting on a body as shown in figure.






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Answer 1

sorry the four forces acting on a body is always perpendicular to each other so I think it is radius 437 square

Answer 2

Solution:

• Here we have to add all the forces along with directions and adding up all together we can get the Resultant Force.

• The basic representation of finding resultant is ,

            $f_{R} =f_{1}+f_{2}-f_{3}-f_{4}--- > eq1$

• let's write all the forces along with components,

         $f_{1}=mgsin30^{0} , f_{2}= mgsin 40^{0} , f_{3}=mgsin10^{0} , f_{4}=mgsin60^{0}$

• lets sub in eq1 and we get,

         $f_{R}=1000(\frac{1}{2})+400(0.6428)-2000(0.1736)-600(\frac{\sqrt{3} }{2} )$

             $=500+257.12-347.2-519.6$

             $=-109.68$

• therefore the resultant is $109.68$ and the '-' sign indicates that the resultant is in a negative direction.

answer is 109(approx)

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