Question

1. Differentiation of function f(x,y,z) = sin(x)Sin(y)Sin(z)-Cos(x) Cos(y) Cos(z) w.rity is?
a) f(x,y,z) = Cos(x)Cos(y)Sin(z) + sin(x)Sin(y)Cos(z)
b) f(x,y,z) = sin(x)Cos(y)Sin(z) + Cos(x)Sin(y)Cos(z)
c) f(x,y,z) = Cos(x)Cos(y)Cos(z) + sin(x)Sin(y)Sin(z)
d) f(x,y,z) = Sin(x)Sin(y)Sin(z) + Cos(x)Cos(y)Cos(z)
View Answer​

Answer 1

a) f(x,y,z) = Cos(x)Cos(y)Sin(z) + ain (x)Sin(y)Cos(z)

Answer 2

Answer:

f(x, y, z) = Sin(x)cosy(y)Sin(z) + Cos(x) sin(y) Cos(z)

Step-by-step explanation:

Since the function has 3 independent variables hence during differentiation we have to consider x and z as constant and differentiate it w.r.t. Y,

f’(x, y, z) = Sin(x)Cos(y)Sin(z) + Cos(x)Sin(y)Cos(z).