Question

1.Discuss briefly the Hertz experiment​

Answer 1

Answer:

Hertz experiment consists of two metallic plates of equal size, placed 60 cm apart, held parallel to each other. Two small spheres S1 and S2 are placed closed to each other and connected to the plates A and B by thick metalic rods respectively. Using an induction coil the spheres are charged to high value.

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Answer 2

Answer:

Hertz was able to produce electromagnetic waves of frequency about 5×10

7

Hz. Here the plates A and B acts an a capacitor having small capacitance value C and connecting wire provide low inductance L. Thus the plates and the rods (with spheres) constitutes and LC combination. The high frequency oscillation of charges between the plates is given by

V =

2π

LC

1

Wavelength of the electromagnetic produced is given by

λ=

v

c

=

5×10

7

3×10

8

=6m

An open metallic ring of diameter 0.70 m having small metallic spheres acts as a detector. This constitutes another LC combination whose frequency can be varied by varying its diameter.

Explanation:

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