1. Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.
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Solution:-
Let the one part be 'x'
then the other part will be (184-x)
According to the question: 1/3rd of one part may exceed 1/7th of the other part by 8 ⇒ 1/3*x = 1/7 (184-x) + 8
⇒ x/3 = 1/7 (184-x) +8
⇒ x/3 = (184-x)/7 + 8/1
⇒ x/3 = (184-x + 56)/7
After cross multiplication,
⇒ 7x = 552 - 3x +168
⇒ 7x + 3x = 552 + 168
⇒ 10x = 720
⇒ x =720/10
⇒ x = 72 (one part)
Second part = 184 - 72 = 112
Answer.
Let the one part be 'x'
then the other part will be (184-x)
According to the question: 1/3rd of one part may exceed 1/7th of the other part by 8 ⇒ 1/3*x = 1/7 (184-x) + 8
⇒ x/3 = 1/7 (184-x) +8
⇒ x/3 = (184-x)/7 + 8/1
⇒ x/3 = (184-x + 56)/7
After cross multiplication,
⇒ 7x = 552 - 3x +168
⇒ 7x + 3x = 552 + 168
⇒ 10x = 720
⇒ x =720/10
⇒ x = 72 (one part)
Second part = 184 - 72 = 112
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