Question

1. Divide and write The quotient and the remaindes. 3x - 3x² - 12 + x^4+ x^3= (2+x²)​

Answer 1

Answer:

$\mathrm{Long\:division}\:\frac{3x-3x^2-12+x^4+x^3}{\left(2+x^2\right)}:\quad x^2+x-5+\frac{x-2}{x^2+2}$

Step-by-step explanation:

$\mathrm{\frac{3x-3x^2-12+x^4+x^3}{\left(2+x^2\right)}}$

$\mathrm{=x^2+\frac{x^3-5x^2+3x-12}{x^2+2}}$

$\mathrm{=x^2+x+\frac{-5x^2+x-12}{x^2+2}}$

$\mathrm{=x^2+x-5+\frac{x-2}{x^2+2}}$