Question

1 divided by x minus 3 minus 1 divided by x minus 5 is equal to 1 by 6 find the roots of the equation by quadratic formula​

Answer 1

Answer:

$\frac{1}{x - 3} - \frac{1}{x - 5} = \frac{1}{6} \\ = > \frac{x - 5 - x + 3}{ (x - 3)(x - 5)} = \frac{1}{ 6} \\ = > \frac{ - 2}{ {x}^{2} - 8x + 15 } = \frac{1}{6} \\ = > {x}^{2} - 8x + 15 = - 12 \\ = > {x}^{2} - 8x + 27 = 0 \\ = > x = \frac{8 \pm \sqrt{ {8}^{2} - 4 \times 1 \times 27} }{2 \times 1} \\ = > x = \frac{8 \pm \sqrt{64 -10 8} }{2} \\ = > x = \frac{8 \pm \sqrt{ - 44} }{2}$

it is an imaJINary number