Question

1
dy
is
Let y = x 2 + logs x + 6. Then​

Answer 1

hey buddy hope it will be helpful to you

Answer 2

Answer:

xlogx)

dx

dy

+y=2xlogx

→ dividing by xlogx , we get

→

dx

dy

+

xlogx

y

=2

Multiplying by IF, we get

→d(IF×y)=2logxdx

→IF=e

∫

xlogx

1

dx

=e

log(logx)

=logx

$$\rightarrow Multiplying by IF, we get

→d(IF×y)=2logxdx

By integrating, we get

→ylogx=∫2logxdx

By using Product Rule on RHS, we get

→ylogx=2[logx∫1−∫((∫1)

dx

d

(logx))dx

→ylogx=2[x(logx−1)]+C

Put x=1, we get

0=2[1(0−1)]+C

C=2

→ylogx=2[x(logx−1)]+2

at x=e

y=2