Physics, asked by paripati14, 11 months ago

1 dyne = to how much erg please tell with solution​

Answers

Answered by Anuj9034151667
0

Explanation:

1 dyn = 1 g⋅cm/s2 = 10−5 kg⋅m/s2 = 10−5 N

1 N = 1 kg⋅m/s2 = 105 g⋅cm/s2 = 105 dyn

Units of force

v.t.e newton

(SI unit) dyne kilogram-force,

kilopond pound-force poundal

1 N ≡ 1 kg⋅m/s2 = 105 dyn ≈ 0.10197 kp ≈ 0.22481 lbf ≈ 7.2330 pdl

1 dyn = 10−5 N ≡ 1 g⋅cm/s2 ≈ 1.0197 × 10−6 kp ≈ 2.2481 × 10−6 lbf ≈ 7.2330 × 10−5 pdl

1 kp = 9.80665 N = 980665 dyn ≡ gn ⋅ (1 kg) ≈ 2.2046 lbf ≈ 70.932 pdl

1 lbf ≈ 4.448222 N ≈ 444822 dyn ≈ 0.45359 kp ≡ gn ⋅ (1 lb) ≈ 32.174 pdl

1 pdl ≈ 0.138255 N ≈ 13825 dyn ≈ 0.014098 kp ≈ 0.031081 lbf

Answered by sumith89
0

Answer:

More information from the unit converter

More information from the unit converterHow many newton in 1 dyne?

The answer is 1.0E-5.

We assume you are converting between newton and dyne.

You can view more details on each measurement unit: newton or dyne

The SI derived unit for force is the newton.

1 newton is equal to 100000 dyne.

Similar questions