1)Each of the 2 equal angles of triangle is twice the third angle.Find the angle of the triangle.
2) Among 2 supplementary angles the measure of the larger angle is 36degree more than the measure of the smaller.find the measure
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1. third angle of the triangle = x (say) First angle of the triangle = 2x second angle of the triangle = 2x sum of angles in a triangle is 180 degrees
1st angle + 2nd angle + 3rd angle = 180degrees 2x+2x+x = 180 degrees 5x = 180 degrees x = 180 divide by 5 x = 36 1st angle = 2x = 36 multiply by 2 2nd angle = 2x = 36 multiply by 2 3rd angle = x = 36
1st angle + 2nd angle + 3rd angle = 180degrees 2x+2x+x = 180 degrees 5x = 180 degrees x = 180 divide by 5 x = 36 1st angle = 2x = 36 multiply by 2 2nd angle = 2x = 36 multiply by 2 3rd angle = x = 36
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