Question

let p(x)=x2-4x+3. find the value of p(0),p(1),p(2),p(3) and obtain zeroes of the polynomial p(x)

Answer 1

p(0)=0-0+3
=3
p(1)=1-4+3
=0
p(2)=4-8+3
=1
p(3)=9-12+3
=0
therefore the zeroes of the polynomial are 1 and 3