Question

1.      Each pillar in a temple is in the shape of a cylinder of radius 1.4m and height 4m. Find

a)     Curved surface area of one pillar

b)     Curved surface area of 50 such pillars

c)      Cost of whitewashing the curved surface area of 50 pillars at rate of ₹10per m2.​

Answer 1

we have r = 1.4 m

h = 4 m

a)Curved surface area of cylinder =

$2\pi \: r \: h$

Substituting all the values we get ,

$2 \times \frac{22}{7} \times 1.4 \times 4$

=

$35 .2\: m {}^{2}$

Now we know 1 pillar curved surface area

Now for 50 pillars

we multiply 1 cylinder c.s.a ×50 = 35.2×50 =

$1760 \: m {}^{2}$

Now cost for per meter square is given to be 10 rupees .now for 1760 meter square =

$1760 \times 10$

= 17600 rupees

Answer 2

Answer:

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