Question

1) एक दोन अंकी संख्या तिच्या अंकांच्या बेरजेच्या आठ
पट आहे. अंकांची अदलाबदल करून आलेली संख्या ही
मूळ संख्येपेक्षा 45 ने कमी आहे, तर ती संख्या शोधा.​

Answer 1

Given :- A two - digit number is eight times the sum of its digits . If 45 is subtracted from the numbers, the position of digits get interchanged . Find the number. ?

Solution :-

Let us assume that, the original number is 10x + y, where y is unit digit and x is ten's digit .

given that,

→ 10x + y = 8(x + y)

→ 10x + y = 8x + 8y

→ 10x - 8x = 8y - y

→ 2x = 7y

→ x/y = 7/2

→ x : y = 7 : 2

also,

→ (10x + y) - 45 = (10y + x)

→ 10x - x + y - 10y = 45

→ 9x - 9y = 45

→ 9(x - y) = 45

→ x - y = 5 ---------- (2)

then,

→ 7z - 2z = 5

→ 5z = 5

→ z = 1 .

therefore,

→ x = 7z = 7

→ y = 2z = 2 .

hence,

→ Original number = (10x + y) = (10 * 7 + 2) = 70 + 2 = 72 (Ans.)

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