Question

1. Ethyl bromide is heated with KCN.​

Answer 1

Answer:

$<marquee>Et-Br + NaCN or KCN →Et-CN i.e. cyanide will be formed. Et-Br + AgCN → Et-NC i.e. isocyanide will be formed. ... Hence they have cyanide ion (CN-) in which the -ve charge lies on carbon. So, in the reaction C is our nucleophilic atom</marquee>$

Answer 2

Explanation:

Et-Br + NaCN or KCN →Et-CN i.e. cyanide will be formed. Et-Br + AgCN → Et-NC i.e. isocyanide will be formed. ... Hence they have cyanide ion (CN-) in which the -ve charge lies on carbon. So, in the reaction C is our nucleophilic atom.